TSTP Solution File: ITP065^1 by Duper---1.0
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%------------------------------------------------------------------------------
% File : Duper---1.0
% Problem : ITP065^1 : TPTP v8.1.2. Released v7.5.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n017.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 03:38:35 EDT 2023
% Result : Theorem 4.24s 4.55s
% Output : Proof 4.24s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.10/0.11 % Problem : ITP065^1 : TPTP v8.1.2. Released v7.5.0.
% 0.10/0.12 % Command : duper %s
% 0.11/0.32 % Computer : n017.cluster.edu
% 0.11/0.32 % Model : x86_64 x86_64
% 0.11/0.32 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.11/0.32 % Memory : 8042.1875MB
% 0.11/0.32 % OS : Linux 3.10.0-693.el7.x86_64
% 0.11/0.32 % CPULimit : 300
% 0.11/0.32 % WCLimit : 300
% 0.11/0.32 % DateTime : Sun Aug 27 14:26:12 EDT 2023
% 0.11/0.32 % CPUTime :
% 4.24/4.55 SZS status Theorem for theBenchmark.p
% 4.24/4.55 SZS output start Proof for theBenchmark.p
% 4.24/4.55 Clause #0 (by assumption #[]): Eq (Eq heapIm229596387mpty_b fun T => Eq T e_b) True
% 4.24/4.55 Clause #13 (by assumption #[]): Eq (Not (heapIm229596387mpty_b e_b)) True
% 4.24/4.55 Clause #14 (by clausification #[13]): Eq (heapIm229596387mpty_b e_b) False
% 4.24/4.55 Clause #44 (by clausification #[0]): Eq heapIm229596387mpty_b fun T => Eq T e_b
% 4.24/4.55 Clause #45 (by argument congruence #[44]): ∀ (a : tree_b), Eq (heapIm229596387mpty_b a) ((fun T => Eq T e_b) a)
% 4.24/4.55 Clause #49 (by betaEtaReduce #[45]): ∀ (a : tree_b), Eq (heapIm229596387mpty_b a) (Eq a e_b)
% 4.24/4.55 Clause #50 (by clausify Prop equality #[49]): ∀ (a : tree_b), Or (Eq (heapIm229596387mpty_b a) True) (Eq (Eq a e_b) False)
% 4.24/4.55 Clause #57 (by clausification #[50]): ∀ (a : tree_b), Or (Eq (heapIm229596387mpty_b a) True) (Ne a e_b)
% 4.24/4.55 Clause #58 (by destructive equality resolution #[57]): Eq (heapIm229596387mpty_b e_b) True
% 4.24/4.55 Clause #59 (by superposition #[58, 14]): Eq True False
% 4.24/4.55 Clause #63 (by clausification #[59]): False
% 4.24/4.55 SZS output end Proof for theBenchmark.p
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